Base | Representation |
---|---|
bin | 1011000110010100100000… |
… | …1100001001010011000011 |
3 | 1121012121121220121211222111 |
4 | 2301211020030021103003 |
5 | 3044414140041400144 |
6 | 41542025002520151 |
7 | 2366436666664546 |
oct | 261451014112303 |
9 | 47177556554874 |
10 | 12203213231299 |
11 | 3985398806262 |
12 | 1451093506057 |
13 | 6a69b1630b4c |
14 | 3028d273085d |
15 | 162678508534 |
hex | b19483094c3 |
12203213231299 has 2 divisors, whose sum is σ = 12203213231300. Its totient is φ = 12203213231298.
The previous prime is 12203213231273. The next prime is 12203213231371. The reversal of 12203213231299 is 99213231230221.
It is a weak prime.
It is an emirp because it is prime and its reverse (99213231230221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12203213231299 - 219 = 12203212707011 is a prime.
It is not a weakly prime, because it can be changed into another prime (12203213231219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101606615649 + 6101606615650.
It is an arithmetic number, because the mean of its divisors is an integer number (6101606615650).
Almost surely, 212203213231299 is an apocalyptic number.
12203213231299 is a deficient number, since it is larger than the sum of its proper divisors (1).
12203213231299 is an equidigital number, since it uses as much as digits as its factorization.
12203213231299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 40.
The spelling of 12203213231299 in words is "twelve trillion, two hundred three billion, two hundred thirteen million, two hundred thirty-one thousand, two hundred ninety-nine".
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