Base | Representation |
---|---|
bin | 1011000110010100100010… |
… | …1110000011101101101010 |
3 | 1121012121122112100111210121 |
4 | 2301211020232003231222 |
5 | 3044414144330340242 |
6 | 41542025521233454 |
7 | 2366440135362151 |
oct | 261451056035552 |
9 | 47177575314717 |
10 | 12203222121322 |
11 | 39853a2828491 |
12 | 145109649288a |
13 | 6a69b342440b |
14 | 3028d39a6598 |
15 | 1626791b2667 |
hex | b1948b83b6a |
12203222121322 has 4 divisors (see below), whose sum is σ = 18304833181986. Its totient is φ = 6101611060660.
The previous prime is 12203222121313. The next prime is 12203222121331. The reversal of 12203222121322 is 22312122230221.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (12203222121313) and next prime (12203222121331).
It can be written as a sum of positive squares in only one way, i.e., 8240809403761 + 3962412717561 = 2870681^2 + 1990581^2 .
It is a super-2 number, since 2×122032221213222 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3050805530329 + ... + 3050805530332.
Almost surely, 212203222121322 is an apocalyptic number.
12203222121322 is a deficient number, since it is larger than the sum of its proper divisors (6101611060664).
12203222121322 is an equidigital number, since it uses as much as digits as its factorization.
12203222121322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6101611060663.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12203222121322 its reverse (22312122230221), we get a palindrome (34515344351543).
The spelling of 12203222121322 in words is "twelve trillion, two hundred three billion, two hundred twenty-two million, one hundred twenty-one thousand, three hundred twenty-two".
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