Base | Representation |
---|---|
bin | 10001110000100001000… |
… | …010110111010101011111 |
3 | 11022122212112222201212100 |
4 | 101300201002313111133 |
5 | 124443211212024020 |
6 | 2332335402140143 |
7 | 154110536203554 |
oct | 21604102672537 |
9 | 4278775881770 |
10 | 1220325111135 |
11 | 43059a7909a9 |
12 | 1786104b1653 |
13 | 8b0cb4430a0 |
14 | 430c7a7ca2b |
15 | 21b24275a90 |
hex | 11c210b755f |
1220325111135 has 48 divisors (see below), whose sum is σ = 2278043258400. Its totient is φ = 600748261632.
The previous prime is 1220325111097. The next prime is 1220325111197. The reversal of 1220325111135 is 5311115230221.
1220325111135 is a `hidden beast` number, since 1 + 2 + 2 + 0 + 32 + 511 + 113 + 5 = 666.
It is not a de Polignac number, because 1220325111135 - 224 = 1220308333919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1220325111099 and 1220325111108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 20643801 + ... + 20702829.
It is an arithmetic number, because the mean of its divisors is an integer number (47459234550).
Almost surely, 21220325111135 is an apocalyptic number.
1220325111135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1220325111135 is a deficient number, since it is larger than the sum of its proper divisors (1057718147265).
1220325111135 is a wasteful number, since it uses less digits than its factorization.
1220325111135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94392 (or 94389 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
The spelling of 1220325111135 in words is "one trillion, two hundred twenty billion, three hundred twenty-five million, one hundred eleven thousand, one hundred thirty-five".
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