Base | Representation |
---|---|
bin | 10001110000100001100… |
… | …010001001100001111001 |
3 | 11022122220010102101111120 |
4 | 101300201202021201321 |
5 | 124443220311441441 |
6 | 2332340254015453 |
7 | 154110666001260 |
oct | 21604142114171 |
9 | 4278803371446 |
10 | 1220333312121 |
11 | 4305a4382480 |
12 | 1786131a7589 |
13 | 8b100054b41 |
14 | 430c8bb55d7 |
15 | 21b24d45966 |
hex | 11c21889879 |
1220333312121 has 64 divisors (see below), whose sum is σ = 2140309678080. Its totient is φ = 599186211840.
The previous prime is 1220333312111. The next prime is 1220333312129. The reversal of 1220333312121 is 1212133330221.
It is not a de Polignac number, because 1220333312121 - 25 = 1220333312089 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1220333312091 and 1220333312100.
It is not an unprimeable number, because it can be changed into a prime (1220333312129) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1579371 + ... + 2221503.
It is an arithmetic number, because the mean of its divisors is an integer number (33442338720).
Almost surely, 21220333312121 is an apocalyptic number.
1220333312121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1220333312121 is a deficient number, since it is larger than the sum of its proper divisors (919976365959).
1220333312121 is a wasteful number, since it uses less digits than its factorization.
1220333312121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 642606.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1220333312121 its reverse (1212133330221), we get a palindrome (2432466642342).
The spelling of 1220333312121 in words is "one trillion, two hundred twenty billion, three hundred thirty-three million, three hundred twelve thousand, one hundred twenty-one".
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