Base | Representation |
---|---|
bin | 10001110000101000000… |
… | …110000111101011001001 |
3 | 11022200011210120200112122 |
4 | 101300220012013223021 |
5 | 124443432002430001 |
6 | 2332355225421025 |
7 | 154113503530622 |
oct | 21605006075311 |
9 | 4280153520478 |
10 | 1220443405001 |
11 | 430650537927 |
12 | 17864403a775 |
13 | 8b119ac0562 |
14 | 430d9672a49 |
15 | 21b2e840b1b |
hex | 11c28187ac9 |
1220443405001 has 2 divisors, whose sum is σ = 1220443405002. Its totient is φ = 1220443405000.
The previous prime is 1220443404949. The next prime is 1220443405009. The reversal of 1220443405001 is 1005043440221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 909637155001 + 310806250000 = 953749^2 + 557500^2 .
It is an emirp because it is prime and its reverse (1005043440221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1220443405001 - 238 = 945565498057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1220443405009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610221702500 + 610221702501.
It is an arithmetic number, because the mean of its divisors is an integer number (610221702501).
Almost surely, 21220443405001 is an apocalyptic number.
It is an amenable number.
1220443405001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220443405001 is an equidigital number, since it uses as much as digits as its factorization.
1220443405001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 1220443405001 its reverse (1005043440221), we get a palindrome (2225486845222).
The spelling of 1220443405001 in words is "one trillion, two hundred twenty billion, four hundred forty-three million, four hundred five thousand, one".
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