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1220953013257 is a prime number
BaseRepresentation
bin10001110001000110011…
…110000111110000001001
311022201111022111110122111
4101301012132013300021
5130001002432411012
62332521552222321
7154132232243155
oct21610636076011
94281438443574
101220953013257
1143089216707a
1217876683a9a1
138b19b55aac3
144314720a065
1521b5e455ba7
hex11c46787c09

1220953013257 has 2 divisors, whose sum is σ = 1220953013258. Its totient is φ = 1220953013256.

The previous prime is 1220953013249. The next prime is 1220953013311. The reversal of 1220953013257 is 7523103590221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 661970995456 + 558982017801 = 813616^2 + 747651^2 .

It is a cyclic number.

It is not a de Polignac number, because 1220953013257 - 23 = 1220953013249 is a prime.

It is not a weakly prime, because it can be changed into another prime (1220953013057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610476506628 + 610476506629.

It is an arithmetic number, because the mean of its divisors is an integer number (610476506629).

Almost surely, 21220953013257 is an apocalyptic number.

It is an amenable number.

1220953013257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220953013257 is an equidigital number, since it uses as much as digits as its factorization.

1220953013257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 113400, while the sum is 40.

The spelling of 1220953013257 in words is "one trillion, two hundred twenty billion, nine hundred fifty-three million, thirteen thousand, two hundred fifty-seven".