Base | Representation |
---|---|
bin | 11011110000110010100101… |
… | …110011011000100001100010 |
3 | 121000022122201202000110210221 |
4 | 123300302211303120201202 |
5 | 112000442012133013442 |
6 | 1111404003405313254 |
7 | 34501304412515503 |
oct | 3360624563304142 |
9 | 530278652013727 |
10 | 122100112001122 |
11 | 359a5404099202 |
12 | 1183b9a056582a |
13 | 5318cb6756918 |
14 | 22219697b6baa |
15 | e1b1865e3467 |
hex | 6f0ca5cd8862 |
122100112001122 has 4 divisors (see below), whose sum is σ = 183150168001686. Its totient is φ = 61050056000560.
The previous prime is 122100112001117. The next prime is 122100112001171. The reversal of 122100112001122 is 221100211001221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 88742221655481 + 33357890345641 = 9420309^2 + 5775629^2 .
It is a junction number, because it is equal to n+sod(n) for n = 122100112001096 and 122100112001105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30525028000279 + ... + 30525028000282.
Almost surely, 2122100112001122 is an apocalyptic number.
122100112001122 is a deficient number, since it is larger than the sum of its proper divisors (61050056000564).
122100112001122 is an equidigital number, since it uses as much as digits as its factorization.
122100112001122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61050056000563.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 122100112001122 its reverse (221100211001221), we get a palindrome (343200323002343).
Subtracting 122100112001122 from its reverse (221100211001221), we obtain a palindrome (99000099000099).
The spelling of 122100112001122 in words is "one hundred twenty-two trillion, one hundred billion, one hundred twelve million, one thousand, one hundred twenty-two".
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