Base | Representation |
---|---|
bin | 10001110001001001111… |
… | …011101101100111000011 |
3 | 11022201122100210200121212 |
4 | 101301021323231213003 |
5 | 130001112320232042 |
6 | 2332531425240335 |
7 | 154133536060424 |
oct | 21611173554703 |
9 | 4281570720555 |
10 | 1221011102147 |
11 | 430911a32121 |
12 | 1787821930ab |
13 | 8b1aa5b8c25 |
14 | 43150c0b64b |
15 | 21b645cc482 |
hex | 11c49eed9c3 |
1221011102147 has 2 divisors, whose sum is σ = 1221011102148. Its totient is φ = 1221011102146.
The previous prime is 1221011102141. The next prime is 1221011102249. The reversal of 1221011102147 is 7412011101221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221011102147 - 222 = 1221006907843 is a prime.
It is a super-2 number, since 2×12210111021472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1221011102141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610505551073 + 610505551074.
It is an arithmetic number, because the mean of its divisors is an integer number (610505551074).
Almost surely, 21221011102147 is an apocalyptic number.
1221011102147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221011102147 is an equidigital number, since it uses as much as digits as its factorization.
1221011102147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 1221011102147 its reverse (7412011101221), we get a palindrome (8633022203368).
The spelling of 1221011102147 in words is "one trillion, two hundred twenty-one billion, eleven million, one hundred two thousand, one hundred forty-seven".
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