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12210212103 = 34394652807
BaseRepresentation
bin10110101111100100…
…10000110100000111
31011111221200001010220
423113302100310013
5200001303241403
65335335115423
7611403043005
oct132762206407
934457601126
1012210212103
1151a638a091
122449212b73
1311c788609b
1483b8dba75
154b6e45953
hex2d7c90d07

12210212103 has 8 divisors (see below), whose sum is σ = 16658894208. Its totient is φ = 7950835704.

The previous prime is 12210212083. The next prime is 12210212111. The reversal of 12210212103 is 30121201221.

12210212103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12210212103 - 218 = 12209949959 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12210212123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47326275 + ... + 47326532.

It is an arithmetic number, because the mean of its divisors is an integer number (2082361776).

Almost surely, 212210212103 is an apocalyptic number.

12210212103 is a deficient number, since it is larger than the sum of its proper divisors (4448682105).

12210212103 is an equidigital number, since it uses as much as digits as its factorization.

12210212103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94652853.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12210212103 its reverse (30121201221), we get a palindrome (42331413324).

The spelling of 12210212103 in words is "twelve billion, two hundred ten million, two hundred twelve thousand, one hundred three".

Divisors: 1 3 43 129 94652807 283958421 4070070701 12210212103