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1221024433 is a prime number
BaseRepresentation
bin100100011000111…
…0101101010110001
310011002120110122011
41020301311222301
510000040240213
6321054442521
742154351666
oct11061655261
93132513564
101221024433
11577266802
122a0b03441
13165c75c85
14b8243a6d
15722e003d
hex48c75ab1

1221024433 has 2 divisors, whose sum is σ = 1221024434. Its totient is φ = 1221024432.

The previous prime is 1221024397. The next prime is 1221024443. The reversal of 1221024433 is 3344201221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 863360689 + 357663744 = 29383^2 + 18912^2 .

It is an emirp because it is prime and its reverse (3344201221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1221024433 - 217 = 1220893361 is a prime.

It is not a weakly prime, because it can be changed into another prime (1221024443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610512216 + 610512217.

It is an arithmetic number, because the mean of its divisors is an integer number (610512217).

Almost surely, 21221024433 is an apocalyptic number.

It is an amenable number.

1221024433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221024433 is an equidigital number, since it uses as much as digits as its factorization.

1221024433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 1221024433 is about 34943.1600316857. The cubic root of 1221024433 is about 1068.8287276547.

Adding to 1221024433 its reverse (3344201221), we get a palindrome (4565225654).

The spelling of 1221024433 in words is "one billion, two hundred twenty-one million, twenty-four thousand, four hundred thirty-three".