Base | Representation |
---|---|
bin | 1011000110101110111011… |
… | …0001100011000100010011 |
3 | 1121020021221000022111112111 |
4 | 2301223232301203010103 |
5 | 3100023200033140311 |
6 | 41545200305410151 |
7 | 2400110456133412 |
oct | 261535661430423 |
9 | 47207830274474 |
10 | 12210303021331 |
11 | 39883a6808468 |
12 | 1452531939957 |
13 | 6a757141428c |
14 | 302da6181479 |
15 | 162940b5bd21 |
hex | b1aeec63113 |
12210303021331 has 2 divisors, whose sum is σ = 12210303021332. Its totient is φ = 12210303021330.
The previous prime is 12210303021289. The next prime is 12210303021349. The reversal of 12210303021331 is 13312030301221.
12210303021331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12210303021331 - 217 = 12210302890259 is a prime.
It is a super-2 number, since 2×122103030213312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12210303021361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105151510665 + 6105151510666.
It is an arithmetic number, because the mean of its divisors is an integer number (6105151510666).
Almost surely, 212210303021331 is an apocalyptic number.
12210303021331 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210303021331 is an equidigital number, since it uses as much as digits as its factorization.
12210303021331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 12210303021331 its reverse (13312030301221), we get a palindrome (25522333322552).
The spelling of 12210303021331 in words is "twelve trillion, two hundred ten billion, three hundred three million, twenty-one thousand, three hundred thirty-one".
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