Base | Representation |
---|---|
bin | 10110101111100110… |
… | …00001011001111011 |
3 | 1011111222001011011022 |
4 | 23113303001121323 |
5 | 200001331124011 |
6 | 5335343253055 |
7 | 611404532162 |
oct | 132763013173 |
9 | 34458034138 |
10 | 12210411131 |
11 | 51a6505676 |
12 | 24492aa18b |
13 | 11c7925859 |
14 | 83b9503d9 |
15 | 4b6e848db |
hex | 2d7cc167b |
12210411131 has 2 divisors, whose sum is σ = 12210411132. Its totient is φ = 12210411130.
The previous prime is 12210411077. The next prime is 12210411137. The reversal of 12210411131 is 13111401221.
It is a strong prime.
It is an emirp because it is prime and its reverse (13111401221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12210411131 - 214 = 12210394747 is a prime.
It is a super-2 number, since 2×122104111312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12210411137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105205565 + 6105205566.
It is an arithmetic number, because the mean of its divisors is an integer number (6105205566).
Almost surely, 212210411131 is an apocalyptic number.
12210411131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210411131 is an equidigital number, since it uses as much as digits as its factorization.
12210411131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12210411131 its reverse (13111401221), we get a palindrome (25321812352).
The spelling of 12210411131 in words is "twelve billion, two hundred ten million, four hundred eleven thousand, one hundred thirty-one".
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