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122104514533153 is a prime number
BaseRepresentation
bin11011110000110110101100…
…001101101101011100100001
3121000100002002120011021101211
4123300312230031231130201
5112001030021210030103
61111410012315030121
734501521461441035
oct3360665415553441
9530302076137354
10122104514533153
11359a7263217729
121184080aa3b341
135319538895269
142221c663901c5
15e1b342d7c36d
hex6f0dac36d721

122104514533153 has 2 divisors, whose sum is σ = 122104514533154. Its totient is φ = 122104514533152.

The previous prime is 122104514533123. The next prime is 122104514533163. The reversal of 122104514533153 is 351335415401221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121986458383504 + 118056149649 = 11044748^2 + 343593^2 .

It is a cyclic number.

It is not a de Polignac number, because 122104514533153 - 213 = 122104514524961 is a prime.

It is a super-2 number, since 2×1221045145331532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122104514533123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61052257266576 + 61052257266577.

It is an arithmetic number, because the mean of its divisors is an integer number (61052257266577).

Almost surely, 2122104514533153 is an apocalyptic number.

It is an amenable number.

122104514533153 is a deficient number, since it is larger than the sum of its proper divisors (1).

122104514533153 is an equidigital number, since it uses as much as digits as its factorization.

122104514533153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 122104514533153 its reverse (351335415401221), we get a palindrome (473439929934374).

The spelling of 122104514533153 in words is "one hundred twenty-two trillion, one hundred four billion, five hundred fourteen million, five hundred thirty-three thousand, one hundred fifty-three".