Base | Representation |
---|---|
bin | 1011000110110001111001… |
… | …1110011100100001000101 |
3 | 1121020100222210012220002212 |
4 | 2301230132132130201011 |
5 | 3100031314422221013 |
6 | 41545411534513205 |
7 | 2400136344433154 |
oct | 261543636344105 |
9 | 47210883186085 |
10 | 12211103320133 |
11 | 3988777532833 |
12 | 1452715965805 |
13 | 6a766b170173 |
14 | 30304058759b |
15 | 16298b0426a8 |
hex | b1b1e79c845 |
12211103320133 has 8 divisors (see below), whose sum is σ = 12471301354752. Its totient is φ = 11950921424176.
The previous prime is 12211103320121. The next prime is 12211103320139. The reversal of 12211103320133 is 33102330111221.
12211103320133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12211103320133 - 26 = 12211103320069 is a prime.
It is a super-2 number, since 2×122111033201332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12211103320099 and 12211103320108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12211103320139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2499110 + ... + 5537847.
It is an arithmetic number, because the mean of its divisors is an integer number (1558912669344).
Almost surely, 212211103320133 is an apocalyptic number.
It is an amenable number.
12211103320133 is a deficient number, since it is larger than the sum of its proper divisors (260198034619).
12211103320133 is an equidigital number, since it uses as much as digits as its factorization.
12211103320133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8069331.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12211103320133 its reverse (33102330111221), we get a palindrome (45313433431354).
The spelling of 12211103320133 in words is "twelve trillion, two hundred eleven billion, one hundred three million, three hundred twenty thousand, one hundred thirty-three".
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