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122111200100102 = 261055600050051
BaseRepresentation
bin11011110000111100111010…
…101101000111111100000110
3121000100201100111020021010112
4123300330322231013330012
5112001132214211200402
61111413035541553022
734502146242015623
oct3360747255077406
9530321314207115
10122111200100102
11359aa08402a074
1211841b75a15772
13531a0629b8b35
1422222dc25b34a
15e1b5d4c85e52
hex6f0f3ab47f06

122111200100102 has 4 divisors (see below), whose sum is σ = 183166800150156. Its totient is φ = 61055600050050.

The previous prime is 122111200100089. The next prime is 122111200100107. The reversal of 122111200100102 is 201001002111221.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1221112001001023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122111200100107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30527800025024 + ... + 30527800025027.

It is an arithmetic number, because the mean of its divisors is an integer number (45791700037539).

Almost surely, 2122111200100102 is an apocalyptic number.

122111200100102 is a deficient number, since it is larger than the sum of its proper divisors (61055600050054).

122111200100102 is an equidigital number, since it uses as much as digits as its factorization.

122111200100102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61055600050053.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 122111200100102 its reverse (201001002111221), we get a palindrome (323112202211323).

The spelling of 122111200100102 in words is "one hundred twenty-two trillion, one hundred eleven billion, two hundred million, one hundred thousand, one hundred two".

Divisors: 1 2 61055600050051 122111200100102