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12211121004763 is a prime number
BaseRepresentation
bin1011000110110001111110…
…0001111010000011011011
31121020101001000111100212011
42301230133201322003123
53100031333434123023
641545413405530351
72400136650646642
oct261543741720333
947211030440764
1012211121004763
11398878651152a
12145271b8739b7
136a7671a22745
14303042a6c359
1516298c88750d
hexb1b1f87a0db

12211121004763 has 2 divisors, whose sum is σ = 12211121004764. Its totient is φ = 12211121004762.

The previous prime is 12211121004751. The next prime is 12211121004923. The reversal of 12211121004763 is 36740012111221.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12211121004763 is a prime.

It is a super-2 number, since 2×122111210047632 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12211121044763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105560502381 + 6105560502382.

It is an arithmetic number, because the mean of its divisors is an integer number (6105560502382).

Almost surely, 212211121004763 is an apocalyptic number.

12211121004763 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211121004763 is an equidigital number, since it uses as much as digits as its factorization.

12211121004763 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 12211121004763 its reverse (36740012111221), we get a palindrome (48951133115984).

The spelling of 12211121004763 in words is "twelve trillion, two hundred eleven billion, one hundred twenty-one million, four thousand, seven hundred sixty-three".