Base | Representation |
---|---|
bin | 10001110001001111111… |
… | …101000110111110101110 |
3 | 11022201220101220111211211 |
4 | 101301033331012332232 |
5 | 130001314201202002 |
6 | 2332545434505034 |
7 | 154136203600564 |
oct | 21611775067656 |
9 | 4281811814754 |
10 | 1221112131502 |
11 | 430963a66a5a |
12 | 1787abb9517a |
13 | 8b1c5500103 |
14 | 431603c9a34 |
15 | 21b6d3d6dd7 |
hex | 11c4ff46fae |
1221112131502 has 4 divisors (see below), whose sum is σ = 1831668197256. Its totient is φ = 610556065750.
The previous prime is 1221112131451. The next prime is 1221112131553. The reversal of 1221112131502 is 2051312111221.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1221112131451) and next prime (1221112131553).
It is a super-3 number, since 3×12211121315023 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305278032874 + ... + 305278032877.
It is an arithmetic number, because the mean of its divisors is an integer number (457917049314).
Almost surely, 21221112131502 is an apocalyptic number.
1221112131502 is a deficient number, since it is larger than the sum of its proper divisors (610556065754).
1221112131502 is an equidigital number, since it uses as much as digits as its factorization.
1221112131502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 610556065753.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 1221112131502 its reverse (2051312111221), we get a palindrome (3272424242723).
The spelling of 1221112131502 in words is "one trillion, two hundred twenty-one billion, one hundred twelve million, one hundred thirty-one thousand, five hundred two".
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