Base | Representation |
---|---|
bin | 111000110111001110… |
… | …0101110110110101001 |
3 | 102200012012110220201111 |
4 | 1301232130232312221 |
5 | 4000041200004433 |
6 | 132033022150321 |
7 | 11552023544326 |
oct | 1615634566651 |
9 | 380165426644 |
10 | 122112109993 |
11 | 47873114675 |
12 | 1b7bb1223a1 |
13 | b6909552b3 |
14 | 5ca5a65b4d |
15 | 329a610dcd |
hex | 1c6e72eda9 |
122112109993 has 2 divisors, whose sum is σ = 122112109994. Its totient is φ = 122112109992.
The previous prime is 122112109967. The next prime is 122112110051. The reversal of 122112109993 is 399901211221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114973211929 + 7138898064 = 339077^2 + 84492^2 .
It is a cyclic number.
It is not a de Polignac number, because 122112109993 - 221 = 122110012841 is a prime.
It is a super-2 number, since 2×1221121099932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122112109963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056054996 + 61056054997.
It is an arithmetic number, because the mean of its divisors is an integer number (61056054997).
Almost surely, 2122112109993 is an apocalyptic number.
It is an amenable number.
122112109993 is a deficient number, since it is larger than the sum of its proper divisors (1).
122112109993 is an equidigital number, since it uses as much as digits as its factorization.
122112109993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 122112109993 in words is "one hundred twenty-two billion, one hundred twelve million, one hundred nine thousand, nine hundred ninety-three".
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