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122112109993 is a prime number
BaseRepresentation
bin111000110111001110…
…0101110110110101001
3102200012012110220201111
41301232130232312221
54000041200004433
6132033022150321
711552023544326
oct1615634566651
9380165426644
10122112109993
1147873114675
121b7bb1223a1
13b6909552b3
145ca5a65b4d
15329a610dcd
hex1c6e72eda9

122112109993 has 2 divisors, whose sum is σ = 122112109994. Its totient is φ = 122112109992.

The previous prime is 122112109967. The next prime is 122112110051. The reversal of 122112109993 is 399901211221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114973211929 + 7138898064 = 339077^2 + 84492^2 .

It is a cyclic number.

It is not a de Polignac number, because 122112109993 - 221 = 122110012841 is a prime.

It is a super-2 number, since 2×1221121099932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122112109963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056054996 + 61056054997.

It is an arithmetic number, because the mean of its divisors is an integer number (61056054997).

Almost surely, 2122112109993 is an apocalyptic number.

It is an amenable number.

122112109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

122112109993 is an equidigital number, since it uses as much as digits as its factorization.

122112109993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 40.

The spelling of 122112109993 in words is "one hundred twenty-two billion, one hundred twelve million, one hundred nine thousand, nine hundred ninety-three".