Base | Representation |
---|---|
bin | 1011000110110010010011… |
… | …1001010010011110111110 |
3 | 1121020101021021212121212001 |
4 | 2301230210321102132332 |
5 | 3100032030010121342 |
6 | 41545430343132514 |
7 | 2400142123035454 |
oct | 261544471223676 |
9 | 47211237777761 |
10 | 12211211020222 |
11 | 3988822303475 |
12 | 1452745a4413a |
13 | 6a768757b726 |
14 | 3030509c09d4 |
15 | 1629957188b7 |
hex | b1b24e527be |
12211211020222 has 4 divisors (see below), whose sum is σ = 18316816530336. Its totient is φ = 6105605510110.
The previous prime is 12211211020213. The next prime is 12211211020259. The reversal of 12211211020222 is 22202011211221.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×122112110202223 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 12211211020222.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3052802755054 + ... + 3052802755057.
It is an arithmetic number, because the mean of its divisors is an integer number (4579204132584).
Almost surely, 212211211020222 is an apocalyptic number.
12211211020222 is a deficient number, since it is larger than the sum of its proper divisors (6105605510114).
12211211020222 is an equidigital number, since it uses as much as digits as its factorization.
12211211020222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6105605510113.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 12211211020222 its reverse (22202011211221), we get a palindrome (34413222231443).
The spelling of 12211211020222 in words is "twelve trillion, two hundred eleven billion, two hundred eleven million, twenty thousand, two hundred twenty-two".
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