Base | Representation |
---|---|
bin | 10110101111101100… |
… | …11101010110010011 |
3 | 1011112000201220221112 |
4 | 23113312131112103 |
5 | 200002043441034 |
6 | 5335414443535 |
7 | 611415303524 |
oct | 132766352623 |
9 | 34460656845 |
10 | 12211312019 |
11 | 51a6a70505 |
12 | 24496635ab |
13 | 11c7b7c91a |
14 | 83bb0684b |
15 | 4b70b17ce |
hex | 2d7d9d593 |
12211312019 has 2 divisors, whose sum is σ = 12211312020. Its totient is φ = 12211312018.
The previous prime is 12211311947. The next prime is 12211312037. The reversal of 12211312019 is 91021311221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12211312019 is a prime.
It is a super-2 number, since 2×122113120192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12211311985 and 12211312003.
It is not a weakly prime, because it can be changed into another prime (12211312049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105656009 + 6105656010.
It is an arithmetic number, because the mean of its divisors is an integer number (6105656010).
Almost surely, 212211312019 is an apocalyptic number.
12211312019 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211312019 is an equidigital number, since it uses as much as digits as its factorization.
12211312019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 12211312019 in words is "twelve billion, two hundred eleven million, three hundred twelve thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •