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1221133302131 is a prime number
BaseRepresentation
bin10001110001010001001…
…101110111100101110011
311022201221212202002111012
4101301101031313211303
5130001340111132011
62332551512341135
7154136551543541
oct21612115674563
94281855662435
101221133302131
11430974a06846
121787b70a47ab
138b1c9a03302
144316313ad91
1521b701b9a8b
hex11c51377973

1221133302131 has 2 divisors, whose sum is σ = 1221133302132. Its totient is φ = 1221133302130.

The previous prime is 1221133302113. The next prime is 1221133302199. The reversal of 1221133302131 is 1312033311221.

Together with previous prime (1221133302113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1221133302131 - 222 = 1221129107827 is a prime.

It is a super-2 number, since 2×12211333021312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1221133302097 and 1221133302106.

It is not a weakly prime, because it can be changed into another prime (1221133301131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610566651065 + 610566651066.

It is an arithmetic number, because the mean of its divisors is an integer number (610566651066).

Almost surely, 21221133302131 is an apocalyptic number.

1221133302131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221133302131 is an equidigital number, since it uses as much as digits as its factorization.

1221133302131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1221133302131 its reverse (1312033311221), we get a palindrome (2533166613352).

The spelling of 1221133302131 in words is "one trillion, two hundred twenty-one billion, one hundred thirty-three million, three hundred two thousand, one hundred thirty-one".