Base | Representation |
---|---|
bin | 10110101111101101… |
… | …10110000100110101 |
3 | 1011112000221001212201 |
4 | 23113312312010311 |
5 | 200002110211201 |
6 | 5335420544501 |
7 | 611416205023 |
oct | 132766660465 |
9 | 34460831781 |
10 | 12211413301 |
11 | 51a702a60a |
12 | 24496b2131 |
13 | 11c7bb6a59 |
14 | 83bb31713 |
15 | 4b70d1801 |
hex | 2d7db6135 |
12211413301 has 4 divisors (see below), whose sum is σ = 12211954272. Its totient is φ = 12210872332.
The previous prime is 12211413287. The next prime is 12211413307. The reversal of 12211413301 is 10331411221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12211413301 - 217 = 12211282229 is a prime.
It is a super-2 number, since 2×122114133012 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12211413307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235081 + ... + 282286.
It is an arithmetic number, because the mean of its divisors is an integer number (3052988568).
Almost surely, 212211413301 is an apocalyptic number.
It is an amenable number.
12211413301 is a deficient number, since it is larger than the sum of its proper divisors (540971).
12211413301 is an equidigital number, since it uses as much as digits as its factorization.
12211413301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540970.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12211413301 its reverse (10331411221), we get a palindrome (22542824522).
The spelling of 12211413301 in words is "twelve billion, two hundred eleven million, four hundred thirteen thousand, three hundred one".
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