Search a number
-
+
12211413307 is a prime number
BaseRepresentation
bin10110101111101101…
…10110000100111011
31011112000221001212221
423113312312010323
5200002110211212
65335420544511
7611416205032
oct132766660473
934460831787
1012211413307
1151a702a615
1224496b2137
1311c7bb6a62
1483bb31719
154b70d1807
hex2d7db613b

12211413307 has 2 divisors, whose sum is σ = 12211413308. Its totient is φ = 12211413306.

The previous prime is 12211413287. The next prime is 12211413343. The reversal of 12211413307 is 70331411221.

It is a weak prime.

It is an emirp because it is prime and its reverse (70331411221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12211413307 - 227 = 12077195579 is a prime.

It is a super-2 number, since 2×122114133072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12211413377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105706653 + 6105706654.

It is an arithmetic number, because the mean of its divisors is an integer number (6105706654).

Almost surely, 212211413307 is an apocalyptic number.

12211413307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211413307 is an equidigital number, since it uses as much as digits as its factorization.

12211413307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 12211413307 its reverse (70331411221), we get a palindrome (82542824528).

The spelling of 12211413307 in words is "twelve billion, two hundred eleven million, four hundred thirteen thousand, three hundred seven".