Base | Representation |
---|---|
bin | 1011000110110011111000… |
… | …0111100110101000001011 |
3 | 1121020102100210011112200201 |
4 | 2301230332013212220023 |
5 | 3100033411324000042 |
6 | 41545540341313031 |
7 | 2400155452034101 |
oct | 261547607465013 |
9 | 47212323145621 |
10 | 12211634203147 |
11 | 3988a1a173025 |
12 | 1452843705777 |
13 | 6a7724149122 |
14 | 303090c9bc71 |
15 | 1629bc95b1b7 |
hex | b1b3e1e6a0b |
12211634203147 has 2 divisors, whose sum is σ = 12211634203148. Its totient is φ = 12211634203146.
The previous prime is 12211634203133. The next prime is 12211634203151. The reversal of 12211634203147 is 74130243611221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12211634203147 is a prime.
It is a super-2 number, since 2×122116342031472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12211634203127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105817101573 + 6105817101574.
It is an arithmetic number, because the mean of its divisors is an integer number (6105817101574).
Almost surely, 212211634203147 is an apocalyptic number.
12211634203147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211634203147 is an equidigital number, since it uses as much as digits as its factorization.
12211634203147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 37.
Adding to 12211634203147 its reverse (74130243611221), we get a palindrome (86341877814368).
The spelling of 12211634203147 in words is "twelve trillion, two hundred eleven billion, six hundred thirty-four million, two hundred three thousand, one hundred forty-seven".
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