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12211634203147 is a prime number
BaseRepresentation
bin1011000110110011111000…
…0111100110101000001011
31121020102100210011112200201
42301230332013212220023
53100033411324000042
641545540341313031
72400155452034101
oct261547607465013
947212323145621
1012211634203147
113988a1a173025
121452843705777
136a7724149122
14303090c9bc71
151629bc95b1b7
hexb1b3e1e6a0b

12211634203147 has 2 divisors, whose sum is σ = 12211634203148. Its totient is φ = 12211634203146.

The previous prime is 12211634203133. The next prime is 12211634203151. The reversal of 12211634203147 is 74130243611221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12211634203147 is a prime.

It is a super-2 number, since 2×122116342031472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12211634203127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105817101573 + 6105817101574.

It is an arithmetic number, because the mean of its divisors is an integer number (6105817101574).

Almost surely, 212211634203147 is an apocalyptic number.

12211634203147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211634203147 is an equidigital number, since it uses as much as digits as its factorization.

12211634203147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

Adding to 12211634203147 its reverse (74130243611221), we get a palindrome (86341877814368).

The spelling of 12211634203147 in words is "twelve trillion, two hundred eleven billion, six hundred thirty-four million, two hundred three thousand, one hundred forty-seven".