Base | Representation |
---|---|
bin | 1011000110110101010000… |
… | …0011000001001011111101 |
3 | 1121020110022102102122020210 |
4 | 2301231110003001023331 |
5 | 3100040140014144330 |
6 | 41550041042503033 |
7 | 2400200540100423 |
oct | 261552403011375 |
9 | 47213272378223 |
10 | 12212002099965 |
11 | 3989098901388 |
12 | 1452926964a79 |
13 | 6a778242a355 |
14 | 3030c7aa7113 |
15 | 1629dedcc8b0 |
hex | b1b540c12fd |
12212002099965 has 16 divisors (see below), whose sum is σ = 19558801381248. Its totient is φ = 6506535112896.
The previous prime is 12212002099963. The next prime is 12212002100009. The reversal of 12212002099965 is 56999020021221.
It is not a de Polignac number, because 12212002099965 - 21 = 12212002099963 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12212002099961) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 408276657 + ... + 408306566.
It is an arithmetic number, because the mean of its divisors is an integer number (1222425086328).
Almost surely, 212212002099965 is an apocalyptic number.
12212002099965 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12212002099965 is a deficient number, since it is larger than the sum of its proper divisors (7346799281283).
12212002099965 is an equidigital number, since it uses as much as digits as its factorization.
12212002099965 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 816584228.
The product of its (nonzero) digits is 349920, while the sum is 48.
The spelling of 12212002099965 in words is "twelve trillion, two hundred twelve billion, two million, ninety-nine thousand, nine hundred sixty-five".
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