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12212333000000 = 265672375853
BaseRepresentation
bin1011000110110110011111…
…0001010011010101000000
31121020111011111002002202122
42301231213301103111000
53100041324222000000
641550133543103412
72400211665514520
oct261554761232500
947214144062678
1012212333000000
113989248670491
1214529b9741b68
136a7805b569a3
14303119a01680
15162a0de92085
hexb1b67c53540

12212333000000 has 392 divisors, whose sum is σ = 36125005094016. Its totient is φ = 4004985600000.

The previous prime is 12212332999981. The next prime is 12212333000003. The reversal of 12212333000000 is 33321221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12212333000003) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 160962074 + ... + 161037926.

Almost surely, 212212333000000 is an apocalyptic number.

12212333000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12212333000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18062502547008).

12212333000000 is an abundant number, since it is smaller than the sum of its proper divisors (23912672094016).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12212333000000 is an frugal number, since it uses more digits than its factorization.

12212333000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75925 (or 75890 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 12212333000000 its reverse (33321221), we get a palindrome (12212366321221).

The spelling of 12212333000000 in words is "twelve trillion, two hundred twelve billion, three hundred thirty-three million", and thus it is an aban number.