Base | Representation |
---|---|
bin | 11011110001001110111011… |
… | …101101100011000001111011 |
3 | 121000102120021121211112011101 |
4 | 123301032323231203001323 |
5 | 112001441323322403430 |
6 | 1111425555244112231 |
7 | 34503432512242012 |
oct | 3361167355430173 |
9 | 530376247745141 |
10 | 122130544341115 |
11 | 35a07300386712 |
12 | 11845874235677 |
13 | 531bb265743ab |
14 | 2223215403a79 |
15 | e1bd6816cdca |
hex | 6f13bbb6307b |
122130544341115 has 32 divisors (see below), whose sum is σ = 155779918295040. Its totient is φ = 91730053341696.
The previous prime is 122130544341107. The next prime is 122130544341149. The reversal of 122130544341115 is 511143445031221.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 122130544341115 - 23 = 122130544341107 is a prime.
It is a super-2 number, since 2×1221305443411152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44284195 + ... + 46961164.
It is an arithmetic number, because the mean of its divisors is an integer number (4868122446720).
Almost surely, 2122130544341115 is an apocalyptic number.
122130544341115 is a deficient number, since it is larger than the sum of its proper divisors (33649373953925).
122130544341115 is a wasteful number, since it uses less digits than its factorization.
122130544341115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91245603.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 122130544341115 its reverse (511143445031221), we get a palindrome (633273989372336).
The spelling of 122130544341115 in words is "one hundred twenty-two trillion, one hundred thirty billion, five hundred forty-four million, three hundred forty-one thousand, one hundred fifteen".
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