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122131203110100 = 2232522937510124793
BaseRepresentation
bin11011110001001111100010…
…111110100011010011010100
3121000102121222112102110022200
4123301033202332203103110
5112001444200444010400
61111430144455524500
734503455031550212
oct3361174276432324
9530377875373280
10122131203110100
1135a07609224598
1211845a18989730
13531bbccba8822
142223278ac7cb2
15e1bda5de8b00
hex6f13e2fa34d4

122131203110100 has 432 divisors, whose sum is σ = 406813155468720. Its totient is φ = 30588171264000.

The previous prime is 122131203110099. The next prime is 122131203110159. The reversal of 122131203110100 is 1011302131221.

122131203110100 is a `hidden beast` number, since 1 + 221 + 3 + 120 + 311 + 0 + 10 + 0 = 666.

It can be written as a sum of positive squares in 24 ways, for example, as 57225654375696 + 64905548734404 = 7564764^2 + 8056398^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 4926023304 + ... + 4926048096.

Almost surely, 2122131203110100 is an apocalyptic number.

122131203110100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 122131203110100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (203406577734360).

122131203110100 is an abundant number, since it is smaller than the sum of its proper divisors (284681952358620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122131203110100 is a wasteful number, since it uses less digits than its factorization.

122131203110100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29980 (or 29970 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 122131203110100 its reverse (1011302131221), we get a palindrome (123142505241321).

The spelling of 122131203110100 in words is "one hundred twenty-two trillion, one hundred thirty-one billion, two hundred three million, one hundred ten thousand, one hundred".