Base | Representation |
---|---|
bin | 1011000110111001011101… |
… | …0001101010011000111001 |
3 | 1121020120020000210111222122 |
4 | 2301232113101222120321 |
5 | 3100044442240342332 |
6 | 41550345013531025 |
7 | 2400240514145351 |
oct | 261562721523071 |
9 | 47216200714878 |
10 | 12213130012217 |
11 | 3989617550572 |
12 | 1452ba0643a75 |
13 | 6a7902001954 |
14 | 3031937cdb61 |
15 | 162a58e28c12 |
hex | b1b9746a639 |
12213130012217 has 2 divisors, whose sum is σ = 12213130012218. Its totient is φ = 12213130012216.
The previous prime is 12213130012147. The next prime is 12213130012339. The reversal of 12213130012217 is 71221003131221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6958495306816 + 5254634705401 = 2637896^2 + 2292299^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12213130012217 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213130012717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106565006108 + 6106565006109.
It is an arithmetic number, because the mean of its divisors is an integer number (6106565006109).
Almost surely, 212213130012217 is an apocalyptic number.
It is an amenable number.
12213130012217 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213130012217 is an equidigital number, since it uses as much as digits as its factorization.
12213130012217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 12213130012217 its reverse (71221003131221), we get a palindrome (83434133143438).
The spelling of 12213130012217 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty million, twelve thousand, two hundred seventeen".
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