Base | Representation |
---|---|
bin | 1011000110111001011101… |
… | …1001101000100111011001 |
3 | 1121020120020011201200202220 |
4 | 2301232113121220213121 |
5 | 3100044443304231410 |
6 | 41550345130414253 |
7 | 2400240541001334 |
oct | 261562731504731 |
9 | 47216204650686 |
10 | 12213132102105 |
11 | 3989618748750 |
12 | 1452ba1291389 |
13 | 6a7902583c7c |
14 | 303193bb561b |
15 | 162a591dd070 |
hex | b1b976689d9 |
12213132102105 has 64 divisors (see below), whose sum is σ = 21518400384000. Its totient is φ = 5865712536320.
The previous prime is 12213132102047. The next prime is 12213132102169. The reversal of 12213132102105 is 50120123131221.
It is not a de Polignac number, because 12213132102105 - 29 = 12213132101593 is a prime.
It is a super-2 number, since 2×122131321021052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 347944846 + ... + 347979944.
It is an arithmetic number, because the mean of its divisors is an integer number (336225006000).
Almost surely, 212213132102105 is an apocalyptic number.
12213132102105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12213132102105 is a deficient number, since it is larger than the sum of its proper divisors (9305268281895).
12213132102105 is a wasteful number, since it uses less digits than its factorization.
12213132102105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54934.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 12213132102105 its reverse (50120123131221), we get a palindrome (62333255233326).
The spelling of 12213132102105 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty-two million, one hundred two thousand, one hundred five".
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