Base | Representation |
---|---|
bin | 1011000110111001011101… |
… | …1010011011111000110001 |
3 | 1121020120020012010100211222 |
4 | 2301232113122123320301 |
5 | 3100044443332441423 |
6 | 41550345135114425 |
7 | 2400240542534525 |
oct | 261562732337061 |
9 | 47216205110758 |
10 | 12213132312113 |
11 | 3989618881507 |
12 | 1452ba1372a15 |
13 | 6a7902628735 |
14 | 303193c2bd85 |
15 | 162a592303c8 |
hex | b1b9769be31 |
12213132312113 has 2 divisors, whose sum is σ = 12213132312114. Its totient is φ = 12213132312112.
The previous prime is 12213132312103. The next prime is 12213132312127. The reversal of 12213132312113 is 31121323131221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12133748122609 + 79384189504 = 3483353^2 + 281752^2 .
It is a cyclic number.
It is not a de Polignac number, because 12213132312113 - 24 = 12213132312097 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213132312103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106566156056 + 6106566156057.
It is an arithmetic number, because the mean of its divisors is an integer number (6106566156057).
Almost surely, 212213132312113 is an apocalyptic number.
It is an amenable number.
12213132312113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213132312113 is an equidigital number, since it uses as much as digits as its factorization.
12213132312113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 26.
Adding to 12213132312113 its reverse (31121323131221), we get a palindrome (43334455443334).
The spelling of 12213132312113 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty-two million, three hundred twelve thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •