Search a number
-
+
12213201333000 = 2335353293317827
BaseRepresentation
bin1011000110111001101110…
…0001101110101100001000
31121020120101222222222201010
42301232123201232230020
53100100114020124000
641550400042323520
72400242341312563
oct261563341565410
947216358888633
1012213201333000
113989653833968
1214530004b95a0
136a7913a136b5
1430319d0774da
15162a60315d50
hexb1b9b86eb08

12213201333000 has 512 divisors, whose sum is σ = 39126805885440. Its totient is φ = 3170613555200.

The previous prime is 12213201332987. The next prime is 12213201333013. The reversal of 12213201333000 is 33310231221.

12213201333000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (12213201332987) and next prime (12213201333013).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 14768078587 + ... + 14768079413.

It is an arithmetic number, because the mean of its divisors is an integer number (76419542745).

Almost surely, 212213201333000 is an apocalyptic number.

12213201333000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12213201333000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19563402942720).

12213201333000 is an abundant number, since it is smaller than the sum of its proper divisors (26913604552440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12213201333000 is a wasteful number, since it uses less digits than its factorization.

12213201333000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1514 (or 1500 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12213201333000 its reverse (33310231221), we get a palindrome (12246511564221).

The spelling of 12213201333000 in words is "twelve trillion, two hundred thirteen billion, two hundred one million, three hundred thirty-three thousand".