Base | Representation |
---|---|
bin | 1011000110111001101110… |
… | …1000100101011011100011 |
3 | 1121020120102010101021211202 |
4 | 2301232123220211123203 |
5 | 3100100120000130313 |
6 | 41550400145031415 |
7 | 2400242362506104 |
oct | 261563350453343 |
9 | 47216363337752 |
10 | 12213203130083 |
11 | 398965485105a |
12 | 145300102556b |
13 | 6a79141c2667 |
14 | 30319d3c43ab |
15 | 162a6056d558 |
hex | b1b9ba256e3 |
12213203130083 has 2 divisors, whose sum is σ = 12213203130084. Its totient is φ = 12213203130082.
The previous prime is 12213203130053. The next prime is 12213203130119. The reversal of 12213203130083 is 38003130231221.
It is a weak prime.
It is an emirp because it is prime and its reverse (38003130231221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12213203130083 - 26 = 12213203130019 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12213203130053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106601565041 + 6106601565042.
It is an arithmetic number, because the mean of its divisors is an integer number (6106601565042).
Almost surely, 212213203130083 is an apocalyptic number.
12213203130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213203130083 is an equidigital number, since it uses as much as digits as its factorization.
12213203130083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 12213203130083 in words is "twelve trillion, two hundred thirteen billion, two hundred three million, one hundred thirty thousand, eighty-three".
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