Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …0101010011000011110011 |
3 | 1121020120200122221220221002 |
4 | 2301232202011103003303 |
5 | 3100100330144222212 |
6 | 41550415011552215 |
7 | 2400245145222356 |
oct | 261564205230363 |
9 | 47216618856832 |
10 | 12213311320307 |
11 | 39896aa926a69 |
12 | 14530312bb66b |
13 | 6a7930743046 |
14 | 3031ad90829d |
15 | 162a69cdeac2 |
hex | b1ba21530f3 |
12213311320307 has 2 divisors, whose sum is σ = 12213311320308. Its totient is φ = 12213311320306.
The previous prime is 12213311320211. The next prime is 12213311320393. The reversal of 12213311320307 is 70302311331221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213311320307 - 214 = 12213311303923 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12213311320307.
It is not a weakly prime, because it can be changed into another prime (12213311322307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106655660153 + 6106655660154.
It is an arithmetic number, because the mean of its divisors is an integer number (6106655660154).
Almost surely, 212213311320307 is an apocalyptic number.
12213311320307 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213311320307 is an equidigital number, since it uses as much as digits as its factorization.
12213311320307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 29.
Adding to 12213311320307 its reverse (70302311331221), we get a palindrome (82515622651528).
The spelling of 12213311320307 in words is "twelve trillion, two hundred thirteen billion, three hundred eleven million, three hundred twenty thousand, three hundred seven".
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