Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …1000011001000011111011 |
3 | 1121020120200201111010102201 |
4 | 2301232202020121003323 |
5 | 3100100330401200243 |
6 | 41550415041211031 |
7 | 2400245155141012 |
oct | 261564210310373 |
9 | 47216621433381 |
10 | 12213312131323 |
11 | 3989700330326 |
12 | 1453031630a77 |
13 | 6a7930968234 |
14 | 3031ada79a79 |
15 | 162a69e0004d |
hex | b1ba22190fb |
12213312131323 has 2 divisors, whose sum is σ = 12213312131324. Its totient is φ = 12213312131322.
The previous prime is 12213312131303. The next prime is 12213312131399. The reversal of 12213312131323 is 32313121331221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12213312131323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12213312131291 and 12213312131300.
It is not a weakly prime, because it can be changed into another prime (12213312131303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106656065661 + 6106656065662.
It is an arithmetic number, because the mean of its divisors is an integer number (6106656065662).
Almost surely, 212213312131323 is an apocalyptic number.
12213312131323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213312131323 is an equidigital number, since it uses as much as digits as its factorization.
12213312131323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3888, while the sum is 28.
Adding to 12213312131323 its reverse (32313121331221), we get a palindrome (44526433462544).
The spelling of 12213312131323 in words is "twelve trillion, two hundred thirteen billion, three hundred twelve million, one hundred thirty-one thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •