Base | Representation |
---|---|
bin | 1011000110111010001010… |
… | …1011010111100010001111 |
3 | 1121020120201100201221122110 |
4 | 2301232202223113202033 |
5 | 3100100340223100421 |
6 | 41550420005515103 |
7 | 2400245326106121 |
oct | 261564253274217 |
9 | 47216640657573 |
10 | 12213321300111 |
11 | 3989705522a38 |
12 | 1453034712a93 |
13 | 6a7932828659 |
14 | 3031b0d85211 |
15 | 162a6ab11a76 |
hex | b1ba2ad788f |
12213321300111 has 32 divisors (see below), whose sum is σ = 16380245178880. Its totient is φ = 8094460667904.
The previous prime is 12213321300049. The next prime is 12213321300127. The reversal of 12213321300111 is 11100312331221.
It is not a de Polignac number, because 12213321300111 - 225 = 12213287745679 is a prime.
It is a super-2 number, since 2×122133213001112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12213321300151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1462143711 + ... + 1462152063.
It is an arithmetic number, because the mean of its divisors is an integer number (511882661840).
Almost surely, 212213321300111 is an apocalyptic number.
12213321300111 is a deficient number, since it is larger than the sum of its proper divisors (4166923878769).
12213321300111 is a wasteful number, since it uses less digits than its factorization.
12213321300111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12655.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12213321300111 its reverse (11100312331221), we get a palindrome (23313633631332).
The spelling of 12213321300111 in words is "twelve trillion, two hundred thirteen billion, three hundred twenty-one million, three hundred thousand, one hundred eleven".
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