Base | Representation |
---|---|
bin | 10110101111111101… |
… | …10100100001110001 |
3 | 1011112011212021221012 |
4 | 23113332310201301 |
5 | 200003124112423 |
6 | 5335533440305 |
7 | 611443033466 |
oct | 132776644161 |
9 | 34464767835 |
10 | 12213504113 |
11 | 51a8228458 |
12 | 244a340095 |
13 | 11c8469615 |
14 | 83c11766d |
15 | 4b7396078 |
hex | 2d7fb4871 |
12213504113 has 2 divisors, whose sum is σ = 12213504114. Its totient is φ = 12213504112.
The previous prime is 12213504103. The next prime is 12213504139. The reversal of 12213504113 is 31140531221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12001859809 + 211644304 = 109553^2 + 14548^2 .
It is an emirp because it is prime and its reverse (31140531221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12213504113 - 26 = 12213504049 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213504103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106752056 + 6106752057.
It is an arithmetic number, because the mean of its divisors is an integer number (6106752057).
Almost surely, 212213504113 is an apocalyptic number.
It is an amenable number.
12213504113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213504113 is an equidigital number, since it uses as much as digits as its factorization.
12213504113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
The spelling of 12213504113 in words is "twelve billion, two hundred thirteen million, five hundred four thousand, one hundred thirteen".
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