12213545401331 has 2 divisors, whose sum is σ = 12213545401332. Its totient is φ = 12213545401330.

The previous prime is 12213545401319. The next prime is 12213545401417. The reversal of 12213545401331 is 13310454531221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12213545401331 - 2²² = 12213541207027 is a prime.

It is a super-2 number, since 2×12213545401331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12213545401291 and 12213545401300.

It is not a weakly prime, because it can be changed into another prime (12213545431331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106772700665 + 6106772700666.

It is an arithmetic number, because the mean of its divisors is an integer number (6106772700666).

Almost surely, 2^{12213545401331} is an apocalyptic number.

12213545401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12213545401331 is an equidigital number, since it uses as much as digits as its factorization.

12213545401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 12213545401331 its reverse (13310454531221), we get a palindrome (25523999932552).

The spelling of 12213545401331 in words is "twelve trillion, two hundred thirteen billion, five hundred forty-five million, four hundred one thousand, three hundred thirty-one".