12214004343 has 4 divisors (see below), whose sum is σ = 16285339128. Its totient is φ = 8142669560.

The previous prime is 12214004339. The next prime is 12214004381. The reversal of 12214004343 is 34340041221.

12214004343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12214004343 - 2² = 12214004339 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12214004393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035667388 + ... + 2035667393.

It is an arithmetic number, because the mean of its divisors is an integer number (4071334782).

Almost surely, 2^12214004343 is an apocalyptic number.

12214004343 is a deficient number, since it is larger than the sum of its proper divisors (4071334785).

12214004343 is an equidigital number, since it uses as much as digits as its factorization.

12214004343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4071334784.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 12214004343 its reverse (34340041221), we get a palindrome (46554045564).

The spelling of 12214004343 in words is "twelve billion, two hundred fourteen million, four thousand, three hundred forty-three".