Base | Representation |
---|---|
bin | 1011000110111100110010… |
… | …1000111011000000100011 |
3 | 1121020122112102102221202101 |
4 | 2301233030220323000203 |
5 | 3100103310434131201 |
6 | 41551013515031231 |
7 | 2400301635035656 |
oct | 261571450730043 |
9 | 47218472387671 |
10 | 12214025302051 |
11 | 3989a36956021 |
12 | 14531b043b517 |
13 | 6a7a15639451 |
14 | 30323a68189d |
15 | 162aac824d01 |
hex | b1bcca3b023 |
12214025302051 has 8 divisors (see below), whose sum is σ = 12386355681024. Its totient is φ = 12041703308040.
The previous prime is 12214025302019. The next prime is 12214025302093. The reversal of 12214025302051 is 15020352041221.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12214025302051 - 25 = 12214025302019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12214025302151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 866970 + ... + 5017936.
It is an arithmetic number, because the mean of its divisors is an integer number (1548294460128).
Almost surely, 212214025302051 is an apocalyptic number.
12214025302051 is a deficient number, since it is larger than the sum of its proper divisors (172330378973).
12214025302051 is an equidigital number, since it uses as much as digits as its factorization.
12214025302051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4192481.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 12214025302051 its reverse (15020352041221), we get a palindrome (27234377343272).
The spelling of 12214025302051 in words is "twelve trillion, two hundred fourteen billion, twenty-five million, three hundred two thousand, fifty-one".
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