Base | Representation |
---|---|
bin | 1011000110111100110010… |
… | …1000111011000010000111 |
3 | 1121020122112102102221220002 |
4 | 2301233030220323002013 |
5 | 3100103310434132101 |
6 | 41551013515031515 |
7 | 2400301635036161 |
oct | 261571450730207 |
9 | 47218472387802 |
10 | 12214025302151 |
11 | 3989a36956102 |
12 | 14531b043b59b |
13 | 6a7a156394ca |
14 | 30323a681931 |
15 | 162aac824d6b |
hex | b1bcca3b087 |
12214025302151 has 2 divisors, whose sum is σ = 12214025302152. Its totient is φ = 12214025302150.
The previous prime is 12214025302093. The next prime is 12214025302189. The reversal of 12214025302151 is 15120352041221.
12214025302151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12214025302151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12214025302651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6107012651075 + 6107012651076.
It is an arithmetic number, because the mean of its divisors is an integer number (6107012651076).
Almost surely, 212214025302151 is an apocalyptic number.
12214025302151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12214025302151 is an equidigital number, since it uses as much as digits as its factorization.
12214025302151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 12214025302151 its reverse (15120352041221), we get a palindrome (27334377343372).
The spelling of 12214025302151 in words is "twelve trillion, two hundred fourteen billion, twenty-five million, three hundred two thousand, one hundred fifty-one".
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