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12214115100 = 223252112591901
BaseRepresentation
bin10110110000000010…
…01001101100011100
31011112020000100001100
423120001021230130
5200003303140400
65335554513100
7611451160005
oct133001115434
934466010040
1012214115100
1151a8605500
12244a595790
1311c8621755
1483c2361ac
154b7467100
hex2d8049b1c

12214115100 has 324 divisors, whose sum is σ = 42817025160. Its totient is φ = 2909280000.

The previous prime is 12214115099. The next prime is 12214115117. The reversal of 12214115100 is 151141221.

12214115100 is a `hidden beast` number, since 12 + 2 + 141 + 1 + 510 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 6424150 + ... + 6426050.

Almost surely, 212214115100 is an apocalyptic number.

12214115100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12214115100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21408512580).

12214115100 is an abundant number, since it is smaller than the sum of its proper divisors (30602910060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12214115100 is a wasteful number, since it uses less digits than its factorization.

12214115100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2002 (or 1981 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 18.

Adding to 12214115100 its reverse (151141221), we get a palindrome (12365256321).

The spelling of 12214115100 in words is "twelve billion, two hundred fourteen million, one hundred fifteen thousand, one hundred".