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12214134305455 = 519971223248303
BaseRepresentation
bin1011000110111101001100…
…1000101111001010101111
31121020122211000112220022111
42301233103020233022233
53100104021340233310
641551032411224451
72400304430410105
oct261572310571257
947218730486274
1012214134305455
113989a92436985
121453220a48127
136a7a320b2cc4
1430324ad37c75
15162ab71a728a
hexb1bd322f2af

12214134305455 has 8 divisors (see below), whose sum is σ = 14664300668352. Its totient is φ = 9766414443168.

The previous prime is 12214134305431. The next prime is 12214134305479. The reversal of 12214134305455 is 55450343141221.

It is an interprime number because it is at equal distance from previous prime (12214134305431) and next prime (12214134305479).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12214134305455 - 211 = 12214134303407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 611614167 + ... + 611634136.

It is an arithmetic number, because the mean of its divisors is an integer number (1833037583544).

Almost surely, 212214134305455 is an apocalyptic number.

12214134305455 is a deficient number, since it is larger than the sum of its proper divisors (2450166362897).

12214134305455 is a wasteful number, since it uses less digits than its factorization.

12214134305455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1223250305.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 12214134305455 its reverse (55450343141221), we get a palindrome (67664477446676).

The spelling of 12214134305455 in words is "twelve trillion, two hundred fourteen billion, one hundred thirty-four million, three hundred five thousand, four hundred fifty-five".

Divisors: 1 5 1997 9985 1223248303 6116241515 2442826861091 12214134305455