Base | Representation |
---|---|
bin | 1011000110111101001110… |
… | …1000000101011010001111 |
3 | 1121020122211121000101200212 |
4 | 2301233103220011122033 |
5 | 3100104030441214043 |
6 | 41551033303313035 |
7 | 2400304560304040 |
oct | 261572350053217 |
9 | 47218747011625 |
10 | 12214142523023 |
11 | 3989a97039961 |
12 | 145322374b77b |
13 | 6a7a339cc47c |
14 | 30324c0768c7 |
15 | 162ab7c7c018 |
hex | b1bd3a0568f |
12214142523023 has 16 divisors (see below), whose sum is σ = 14215140226560. Its totient is φ = 10277663036256.
The previous prime is 12214142523019. The next prime is 12214142523029. The reversal of 12214142523023 is 32032524141221.
It is not a de Polignac number, because 12214142523023 - 22 = 12214142523019 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12214142523029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20039636 + ... + 20640137.
It is an arithmetic number, because the mean of its divisors is an integer number (888446264160).
Almost surely, 212214142523023 is an apocalyptic number.
12214142523023 is a deficient number, since it is larger than the sum of its proper divisors (2000997703537).
12214142523023 is an equidigital number, since it uses as much as digits as its factorization.
12214142523023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40680566.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 12214142523023 its reverse (32032524141221), we get a palindrome (44246666664244).
The spelling of 12214142523023 in words is "twelve trillion, two hundred fourteen billion, one hundred forty-two million, five hundred twenty-three thousand, twenty-three".
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