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1221415144073 is a prime number
BaseRepresentation
bin10001110001100010000…
…001000000101010001001
311022202200112002010221122
4101301202001000222021
5130002424234102243
62333035501245025
7154146543265265
oct21614201005211
94282615063848
101221415144073
11430aaa008873
12178875563775
138b2432141a7
144318c7450a5
1521b89cdd668
hex11c62040a89

1221415144073 has 2 divisors, whose sum is σ = 1221415144074. Its totient is φ = 1221415144072.

The previous prime is 1221415143961. The next prime is 1221415144087. The reversal of 1221415144073 is 3704415141221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1191092842384 + 30322301689 = 1091372^2 + 174133^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221415144073 - 212 = 1221415139977 is a prime.

It is not a weakly prime, because it can be changed into another prime (1221415144973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610707572036 + 610707572037.

It is an arithmetic number, because the mean of its divisors is an integer number (610707572037).

Almost surely, 21221415144073 is an apocalyptic number.

It is an amenable number.

1221415144073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221415144073 is an equidigital number, since it uses as much as digits as its factorization.

1221415144073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

The spelling of 1221415144073 in words is "one trillion, two hundred twenty-one billion, four hundred fifteen million, one hundred forty-four thousand, seventy-three".