Base | Representation |
---|---|
bin | 100100011001101… |
… | …1110100100000001 |
3 | 10011010101022000001 |
4 | 1020303132210001 |
5 | 10000143012311 |
6 | 321112000001 |
7 | 42161121421 |
oct | 11063364401 |
9 | 3133338001 |
10 | 1221454081 |
11 | 57752a591 |
12 | 2a1090001 |
13 | 1660966c3 |
14 | b8316481 |
15 | 723774c1 |
hex | 48cde901 |
1221454081 has 2 divisors, whose sum is σ = 1221454082. Its totient is φ = 1221454080.
The previous prime is 1221454009. The next prime is 1221454099. The reversal of 1221454081 is 1804541221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1066675600 + 154778481 = 32660^2 + 12441^2 .
It is a cyclic number.
It is not a de Polignac number, because 1221454081 - 217 = 1221323009 is a prime.
It is a super-2 number, since 2×12214540812 = 2983900143983109122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1221452081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610727040 + 610727041.
It is an arithmetic number, because the mean of its divisors is an integer number (610727041).
Almost surely, 21221454081 is an apocalyptic number.
It is an amenable number.
1221454081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221454081 is an equidigital number, since it uses as much as digits as its factorization.
1221454081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 28.
The square root of 1221454081 is about 34949.3073035790. The cubic root of 1221454081 is about 1068.9540776642.
The spelling of 1221454081 in words is "one billion, two hundred twenty-one million, four hundred fifty-four thousand, eighty-one".
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