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12220000003 = 88491380947
BaseRepresentation
bin10110110000101111…
…00110011100000011
31011112122002022121201
423120113212130003
5200011310000003
65340325002031
7611552200111
oct133027463403
934478068551
1012220000003
115200964962
122450553317
1311c9902243
1483cd28ab1
154b7c2ab1d
hex2d85e6703

12220000003 has 4 divisors (see below), whose sum is σ = 12221389800. Its totient is φ = 12218610208.

The previous prime is 12219999977. The next prime is 12220000057. The reversal of 12220000003 is 30000002221.

12220000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12220000003 - 225 = 12186445571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12220000063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681625 + ... + 699322.

It is an arithmetic number, because the mean of its divisors is an integer number (3055347450).

Almost surely, 212220000003 is an apocalyptic number.

12220000003 is a deficient number, since it is larger than the sum of its proper divisors (1389797).

12220000003 is an equidigital number, since it uses as much as digits as its factorization.

12220000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1389796.

The product of its (nonzero) digits is 24, while the sum is 10.

Adding to 12220000003 its reverse (30000002221), we get a palindrome (42220002224).

The spelling of 12220000003 in words is "twelve billion, two hundred twenty million, three", and thus it is an aban number.

Divisors: 1 8849 1380947 12220000003