Base | Representation |
---|---|
bin | 1011000111010011011111… |
… | …1110001100111100011011 |
3 | 1121021020021020120222222111 |
4 | 2301310313332030330123 |
5 | 3100203301434304242 |
6 | 41553502431133151 |
7 | 2400605663512054 |
oct | 261646776147433 |
9 | 47236236528874 |
10 | 12220121009947 |
11 | 3991584806644 |
12 | 14544119741b7 |
13 | 6a84774a51b6 |
14 | 30365808572b |
15 | 162d17a65817 |
hex | b1d37f8cf1b |
12220121009947 has 2 divisors, whose sum is σ = 12220121009948. Its totient is φ = 12220121009946.
The previous prime is 12220121009927. The next prime is 12220121010001. The reversal of 12220121009947 is 74990012102221.
It is a weak prime.
It is an emirp because it is prime and its reverse (74990012102221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12220121009947 - 215 = 12220120977179 is a prime.
It is not a weakly prime, because it can be changed into another prime (12220121009927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110060504973 + 6110060504974.
It is an arithmetic number, because the mean of its divisors is an integer number (6110060504974).
Almost surely, 212220121009947 is an apocalyptic number.
12220121009947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12220121009947 is an equidigital number, since it uses as much as digits as its factorization.
12220121009947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 40.
The spelling of 12220121009947 in words is "twelve trillion, two hundred twenty billion, one hundred twenty-one million, nine thousand, nine hundred forty-seven".
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