Base | Representation |
---|---|
bin | 1011000111010110110100… |
… | …0101110111010101100001 |
3 | 1121021022120100112201001102 |
4 | 2301311231011313111201 |
5 | 3100212113111223131 |
6 | 41554131104444145 |
7 | 2400640034553014 |
oct | 261655505672541 |
9 | 47238510481042 |
10 | 12221012211041 |
11 | 39919a1879177 |
12 | 1454620319655 |
13 | 6a858a00a91a |
14 | 30370059137b |
15 | 162d6ae051cb |
hex | b1d6d177561 |
12221012211041 has 2 divisors, whose sum is σ = 12221012211042. Its totient is φ = 12221012211040.
The previous prime is 12221012210999. The next prime is 12221012211119. The reversal of 12221012211041 is 14011221012221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12210279251041 + 10732960000 = 3494321^2 + 103600^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12221012211041 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (12221012211241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110506105520 + 6110506105521.
It is an arithmetic number, because the mean of its divisors is an integer number (6110506105521).
Almost surely, 212221012211041 is an apocalyptic number.
It is an amenable number.
12221012211041 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221012211041 is an equidigital number, since it uses as much as digits as its factorization.
12221012211041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 12221012211041 its reverse (14011221012221), we get a palindrome (26232233223262).
The spelling of 12221012211041 in words is "twelve trillion, two hundred twenty-one billion, twelve million, two hundred eleven thousand, forty-one".
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