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1222110109993 is a prime number
BaseRepresentation
bin10001110010001011011…
…100000110000100101001
311022211110221210001222011
4101302023130012010221
5130010340142004433
62333232444555521
7154203012352063
oct21621334060451
94284427701864
101222110109993
11431326329a73
12178a2a252ba1
138b3241b0126
1443216b6c733
1521bcad193cd
hex11c8b706129

1222110109993 has 2 divisors, whose sum is σ = 1222110109994. Its totient is φ = 1222110109992.

The previous prime is 1222110109931. The next prime is 1222110110059. The reversal of 1222110109993 is 3999010112221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 623510799129 + 598599310864 = 789627^2 + 773692^2 .

It is an emirp because it is prime and its reverse (3999010112221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1222110109993 - 233 = 1213520175401 is a prime.

It is not a weakly prime, because it can be changed into another prime (1222110103993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611055054996 + 611055054997.

It is an arithmetic number, because the mean of its divisors is an integer number (611055054997).

Almost surely, 21222110109993 is an apocalyptic number.

It is an amenable number.

1222110109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1222110109993 is an equidigital number, since it uses as much as digits as its factorization.

1222110109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 40.

The spelling of 1222110109993 in words is "one trillion, two hundred twenty-two billion, one hundred ten million, one hundred nine thousand, nine hundred ninety-three".